Add more to emp-dept exercise.
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		@@ -53,4 +53,39 @@ SELECT ename, sal FROM emp
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	ORDER BY ename ASC, sal DESC;
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						ORDER BY ename ASC, sal DESC;
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-- 16
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					-- 16
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SELECT MAX(sal) FROM emp GROUP BY deptno HAVING deptno IN (10, 20);
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					SELECT (SELECT MAX(sal) FROM emp WHERE deptno=10) "deptno 10",
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						(SELECT MAX(sal) FROM emp WHERE deptno=20) "deptno 20" FROM dual;
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					-- 17
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					SELECT (SELECT MIN(sal) FROM emp WHERE deptno=10) "min sal depnto 10",
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						(SELECT COUNT(*) FROM emp WHERE deptno=20) "employees deptno 20",
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						(SELECT AVG(sal) FROM emp WHERE deptno=30) "avg sal deptno 30" FROM dual;
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					-- 18
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					SELECT ename "NOMBRE", sal+NVL(comm, 0) "SALARIO_TOTAL"
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						FROM emp
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						WHERE deptno=20 ORDER BY ename;
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					-- 19
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					SELECT ename "NOMBRE", sal+NVL(comm, 0) "SALARIO_TOTAL" FROM emp
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						WHERE deptno=10 AND sal > 2000
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						UNION
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						SELECT ename, sal+NVL(comm, 0) FROM emp
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						WHERE sal > 1200
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						ORDER BY SALARIO_TOTAL DESC;
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					-- 20
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					SELECT deptno, ename FROM emp
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						WHERE deptno IN (SELECT deptno FROM emp WHERE ename IN ('JAMES', 'SCOTT')) AND
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						ename NOT IN ('JAMES', 'SCOTT')
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						ORDER BY deptno, ename;
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					-- 21
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					SELECT dname FROM emp JOIN dept ON emp.deptno=dept.deptno GROUP BY dept.dname HAVING COUNT(*) > 4;
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					-- 23
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					SELECT deptno, ROUND(AVG(sal), 2) FROM emp
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						WHERE deptno IN (SELECT DISTINCT deptno FROM emp WHERE job='SALESMAN') GROUP BY deptno;
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					-- 24
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					SELECT deptno, COUNT(*) "NUM" FROM emp GROUP BY deptno ORDER BY NUM DESC LIMIT 1;
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