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phpsg.sh: use already existing OUT_DIR variable.

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Nicolás A. Ortega Froysa 2025-02-19 07:24:07 +01:00
parent 1bb05ad1fc
commit 1704ae6a5c
1 changed files with 1 additions and 1 deletions
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phpsg.sh
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@ -70,7 +70,7 @@ do
OUT_DIR="${OUTPUT_DIR}/${dir:${#SOURCE_DIR}}" OUT_DIR="${OUTPUT_DIR}/${dir:${#SOURCE_DIR}}"
if ! [ -d "$OUT_DIR" ] if ! [ -d "$OUT_DIR" ]
then then
mkdir -p "${OUTPUT_DIR}/${dir:${#SOURCE_DIR}}" mkdir -p "$OUT_DIR"
fi fi
done < <(find "$SOURCE_DIR" -mindepth 1 -type d -print0) done < <(find "$SOURCE_DIR" -mindepth 1 -type d -print0)