Remove parallelization code to start anew.
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parent
9673a4da57
commit
32076a67cd
43
src/main.c
43
src/main.c
@ -122,7 +122,6 @@ int main(int argc, char *argv[]) {
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if(!f_quiet) {
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puts("2\n3");
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}
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mpz_add_ui(num, num, 2);
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} else {
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// Load primes from file
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int err = inputPrimes(file, &primes);
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@ -163,33 +162,14 @@ int main(int argc, char *argv[]) {
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goto releaseMemory;
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}
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#pragma omp parallel default(shared)
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{
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// Variable for sqrt of `privNum'
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mpz_t numRoot;
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mpz_init(numRoot);
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mpz_add_ui(num, num, 2);
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mpz_t privNum;
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mpz_init(privNum);
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mpz_add_ui(privNum, num, omp_get_thread_num() * 2);
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#pragma omp barrier
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do {
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while(run) {
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// Calculate the sqrt(num)
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mpz_sqrt(numRoot, privNum);
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#pragma omp critical
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{
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mpz_out_str(stdout, base, numRoot);
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printf(" - ");
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mpz_out_str(stdout, base, privNum);
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printf("\n");
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}
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// Make sure a number larger than numRoot exists
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while(mpz_cmp(primes.list[primes.end], numRoot) < 0) {
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if(!run)
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goto leaveLoop;
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}
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mpz_sqrt(numRoot, num);
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/**
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* Loop through primes we've found until we get to the sqrt of the
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@ -198,33 +178,26 @@ int main(int argc, char *argv[]) {
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*/
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for(size_t i = 1; mpz_cmp(primes.list[i], numRoot) <= 0; ++i) {
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// If `num' is divisible by a prime then go to the next number
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if(mpz_divisible_p(privNum, primes.list[i]) != 0)
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if(mpz_divisible_p(num, primes.list[i]) != 0)
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goto nextNum;
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}
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// `num' is a prime so we add it to the list and print it
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#pragma omp critical
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{
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if(addToList(&primes, privNum) == 1) {
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if(addToList(&primes, num) == 1) {
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fprintf(stderr, "Failed to allocate more memory for list.\n");
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exitCode = 1;
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run = false;
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}
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if(!f_quiet) {
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if(mpz_out_str(stdout, base, privNum) == 0)
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if(mpz_out_str(stdout, base, num) == 0)
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fprintf(stderr, "Could not print to `stdout'!\n");
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printf("\n");
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}
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}
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nextNum:
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mpz_add_ui(privNum, privNum, omp_get_num_threads() * 2);
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} while(run);
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leaveLoop:
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mpz_clear(privNum);
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mpz_clear(numRoot);
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#pragma omp barrier
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mpz_add_ui(num, num, 2);
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}
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mpz_clear(numRoot);
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printf("Found %zu primes.\n", primes.end);
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